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9.75y^2+3.5y-2=0
a = 9.75; b = 3.5; c = -2;
Δ = b2-4ac
Δ = 3.52-4·9.75·(-2)
Δ = 90.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3.5)-\sqrt{90.25}}{2*9.75}=\frac{-3.5-\sqrt{90.25}}{19.5} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3.5)+\sqrt{90.25}}{2*9.75}=\frac{-3.5+\sqrt{90.25}}{19.5} $
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